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12-09-2012, 12:35 PM | #1 | |
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NFL Tie Breaker
I have a tie breaker question. Lets say 3 teams are tied for the division win. The first three tie breakers are....
Best won loss tie % in games among the clubs Best won loss tied % in division games. Best won loss tie % in common games. The teams are 2-2 in the first. Team A and team B are tied for best Div record while team C has an inferior Div record. The exact same scenario plays out for the 3rd tie breaker. In the link is says this..... Quote:
NFL Tie-Breaking Procedures |
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12-09-2012, 01:12 PM | #2 |
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I would say that Team C is out because of the 2nd tiebreak. Then, yes...you'd go through the tiebreaking scenarios. That's the purpose of having a bunch of tie-breaking rules.
*Could be wrong... |
12-09-2012, 02:10 PM | #3 | ||
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Quote:
Quote:
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12-09-2012, 04:38 PM | #4 |
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Ok thanks. You can eliminate a team even though there was no clear winner. That was where I got hung up.
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12-09-2012, 07:53 PM | #5 |
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Every time I think I have it, I run into another problem.
All 3 teams are in the playoffs. One wins the division. After I drop Team C and determine who wins the division, does Team C automatically become the lower seed? Lets say Team A beats out Team B for the Div. Do I now have to do a sperate tie breaker for B and C to see who gets the 4th and 5th seed? |
12-10-2012, 02:15 AM | #6 |
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I believe C would be ranked third, behind whichever club lost out when the tiebreaker reverted to two teams. Unless, that is, C (and the second place club in the division) is tied with a club or clubs in another division for one or more wild card berths, in which case the seeding for playoff matchup purposes is determined by tiebreakers between the clubs tied for the wild cards.
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12-10-2012, 02:43 PM | #7 |
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Determining Wildcards
Three or More Clubs 1. Apply division tie breaker to eliminate all but the highest ranked club in each division prior to proceeding to step 2. The original seeding within a division upon application of the division tie breaker remains the same for all subsequent applications of the procedure that are necessary to identify the three Wild-Card participants. In your example, then, team B would be seeded fifth and C sixth (the first four seeds are the division winners). |
12-10-2012, 03:06 PM | #8 | ||
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Quote:
Quote:
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12-11-2012, 12:03 AM | #9 |
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The reason I am asking this is because team C swept team B during the season. But Team C lost the 3 team tie breaker for the division.
So am I to assume if another team from a different Div also had a tie then team C would beat out team B? But not if it is only between team B and C in the same Div? |
12-11-2012, 02:30 AM | #10 | ||
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Quote:
Quote:
First, the division tie is settled. The teams have the following results in head-to-head play: Code:
A B C ---------------- A ... 2-0 0-2 B 0-2 ... 2-0 C 2-0 0-2 ... ---------------- 2-2 2-2 2-2 Now the wild card is determined. A, C, and a club outside their division are tied for that. The first step there for a three-way tie is to use the division tiebreakers for clubs within the same division. Since A has a better head-to-head record against C, C is eliminated from contention (and gets third place in the division while A would be in second place). That leaves two teams—A and the club outside its division—tied for the wild card. The two-team method for wild card ties is then used, which starts with head-to-head record. |
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12-11-2012, 07:00 AM | #11 | |
Minors (Rookie Ball)
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Quote:
Determining the playoff seeds in each conference is a three stage process. 1. Determine the four division champions 2. Determine the two wildcard teams 3. Determine the playoff seedings In stage one divisional tiebreakers are used until one team remains. In stage two ties between divisional teams are broken first, then ties between teams from different divisions. So, in your example, teams A, B, and C have equal records in games between each other so all advance to the next step. In step two the best divisional record is shared by teams A, and B. Team C with an inferior divisional record is eliminated from the tiebreaker. Because a team has been eliminated the tiebreaker returns to step one, record in games between tied teams. In games between A and B that team B has the better record. Team B wins the tiebreaker and qualifies for the playoff as the divisional champion. Teams A and C still have a chance at the playoffs via the wildcards. |
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12-11-2012, 07:14 AM | #12 | |
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Quote:
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12-11-2012, 10:55 AM | #13 | |
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Ok thanks. I think I have it. It was a procedural problem I was having.
LGO, this is what I said in post 5. Quote:
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