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Old 09-01-2015, 01:28 PM   #6
thehip41
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Join Date: Aug 2014
Posts: 349
How would 48 games would? You want to play everyone at least three times.

Thats 17 x 3 = 51


I think the best way is to play everyone 3 times and 1 additional game vs a 4th team.

so 16x3 + 1x4 = 52


That way, you play 8 teams 2H 1A and 8 teams 1H 2A, last team, play 2H/2A


You still workin on this RU? If so, I won't bother with it.
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