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Old 05-01-2011, 09:37 AM   #4
professor ape
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Quote:
Originally Posted by Carplos View Post
It's based on PA not AB, and in MLB, as he posted, if you don't qualify, if the number of hits (or other rate stats) divided by the minimum PA still leads your league, you're the batting champ.

That is almost correct. For batting average, you don't divide the hits by the min PA automatically (e.g. 502 in the current MLB) because walks count as PA but not AB. You assume that the PA which the player is short are AB and add them to their actual AB number. You calculate the batting average based on that revised number to see if they are still the batting champion.

Using ChicagoFan's example, his player had a .505 average in 412 AB (208 hits). For this example suppose that there is another player in the league with 600PA and a .420 batting average.

If the .505 batting average player some how had no other plate appearances (BB, HBP, SH, etc) then the calculation would be:

502 min PA - 412 player PA = 90 PA short.
208 H / (412 actual AB + 90 PA short of min) = .414

This .414 average is lower than the qualifying player with the .420 average so the second player wins the batting title.

Using the same player let's say that along with his 412 AB he had 50 walks on the season giving him 462 PA, closer to the 502 minimum but still not there. In this case the calculation is:

502 min PA - 462 player PA = 40 PA short.
208 H / (412 actual AB + 40 PA short of min) = .460

This time the adjusted .460 average is still over the .420 of the top qualifying player. Therefore the player with the .505 average is crowned the batting champion.
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